163 lines
5.4 KiB
Java
163 lines
5.4 KiB
Java
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/* GENERATED SOURCE. DO NOT MODIFY. */
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// © 2016 and later: Unicode, Inc. and others.
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// License & terms of use: http://www.unicode.org/copyright.html
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/*
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*******************************************************************************
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* Copyright (C) 2004-2009, International Business Machines Corporation and *
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* others. All Rights Reserved. *
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*******************************************************************************
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*/
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package android.icu.text;
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/**
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* A post-processor for Chinese text.
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*/
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final class RBNFChinesePostProcessor implements RBNFPostProcessor {
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//private NFRuleSet lastRuleSet;
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private boolean longForm;
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private int format;
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private static final String[] rulesetNames = {
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"%traditional", "%simplified", "%accounting", "%time"
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};
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/**
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* Initialization routine for this instance, called once
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* immediately after first construction and never again.
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*/
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public void init(RuleBasedNumberFormat formatter, String rules) {
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}
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/**
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* Work routine. Post process the output, which was generated by the
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* ruleset with the given name.
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*/
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public void process(StringBuilder buf, NFRuleSet ruleSet) {
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// markers depend on what rule set we are using
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// Commented by johnvu on the if statement since lastRuleSet is never initialized
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//if (ruleSet != lastRuleSet) {
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String name = ruleSet.getName();
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for (int i = 0; i < rulesetNames.length; ++i) {
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if (rulesetNames[i].equals(name)) {
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format = i;
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longForm = i == 1 || i == 3;
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break;
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}
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}
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//}
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if (longForm) {
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for (int i = buf.indexOf("*"); i != -1; i = buf.indexOf("*", i)) {
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buf.delete(i, i+1);
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}
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return;
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}
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final String DIAN = "\u9ede"; // decimal point
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final String[][] markers = {
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{ "\u842c", "\u5104", "\u5146", "\u3007" }, // marker chars, last char is the 'zero'
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{ "\u4e07", "\u4ebf", "\u5146", "\u3007" },
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{ "\u842c", "\u5104", "\u5146", "\u96f6" }
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// need markers for time?
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};
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// remove unwanted lings
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// a '0' (ling) with * might be removed
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// mark off 10,000 'chunks', markers are Z, Y, W (zhao, yii, and wan)
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// already, we avoid two lings in the same chunk -- ling without * wins
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// now, just need to avoid optional lings in adjacent chunks
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// process right to left
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// decision matrix:
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// state, situation
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// state none opt. req.
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// ----- ---- ---- ----
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// none to right none opt. req.
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// opt. to right none clear, none clear right, req.
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// req. to right none clear, none req.
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// mark chunks with '|' for convenience
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{
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String[] m = markers[format];
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for (int i = 0; i < m.length-1; ++i) {
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int n = buf.indexOf(m[i]);
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if (n != -1) {
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buf.insert(n+m[i].length(), '|');
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}
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}
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}
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int x = buf.indexOf(DIAN);
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if (x == -1) {
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x = buf.length();
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}
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int s = 0; // 0 = none to right, 1 = opt. to right, 2 = req. to right
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int n = -1; // previous optional ling
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String ling = markers[format][3];
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while (x >= 0) {
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int m = buf.lastIndexOf("|", x);
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int nn = buf.lastIndexOf(ling, x);
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int ns = 0;
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if (nn > m) {
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ns = (nn > 0 && buf.charAt(nn-1) != '*') ? 2 : 1;
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}
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x = m - 1;
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// actually much simpler, but leave this verbose for now so it's easier to follow
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switch (s*3+ns) {
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case 0: /* none, none */
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s = ns; // redundant
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n = -1;
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break;
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case 1: /* none, opt. */
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s = ns;
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n = nn; // remember optional ling to right
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break;
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case 2: /* none, req. */
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s = ns;
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n = -1;
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break;
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case 3: /* opt., none */
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s = ns;
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n = -1;
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break;
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case 4: /* opt., opt. */
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buf.delete(nn-1, nn+ling.length()); // delete current optional ling
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s = 0;
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n = -1;
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break;
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case 5: /* opt., req. */
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buf.delete(n-1, n+ling.length()); // delete previous optional ling
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s = ns;
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n = -1;
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break;
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case 6: /* req., none */
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s = ns;
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n = -1;
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break;
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case 7: /* req., opt. */
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buf.delete(nn-1, nn+ling.length()); // delete current optional ling
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s = 0;
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n = -1;
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break;
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case 8: /* req., req. */
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s = ns;
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n = -1;
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break;
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default:
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throw new IllegalStateException();
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}
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}
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for (int i = buf.length(); --i >= 0;) {
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char c = buf.charAt(i);
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if (c == '*' || c == '|') {
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buf.delete(i, i+1);
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}
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}
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}
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}
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